Background: I have a large serde_json value that I want to be read-only (the authoritative source is an encrypted SQLite DB and should only be updated when that gets updated)
The issue, I would like a single get function that returns a generic type
use serde_json;
pub struct Configuration {
config: serde_json::Value,
}
impl Configuration {
async fn get(&self, key: &str) -> Result {
let tmp_value: = &self.config["test"];
// This would be repeated for String, bool, etc
if tmp_value.is_i64() {
match tmp_value.as_i64 {
Some(x) => Ok(x),
Err(e) => Err(()),
}
} else {
Err(())
}
}
}
However I get: "mismatched types expected type parameter T found type i64"
Is it even possible to return multiple types from a single function?
EDIT: SOLUTION
Here is the solution I came up with:
pub struct Configuration {}
impl Configuration {
fn get std::str::FromStr>() -> Result {
Ok(T::from_str("1234");
}
}
fn main() {
let my_conf_val = Configuration::get();
}
No. You can only return a single type from the function. You could return the serde_json::Value though so that the code calling this function can get the value it needs itself
Afraid this might have been the case, if Ogeon's suggestion doesn't work out, I'll probably end up with multiple getters, one per type. There aren't that many anyway
Thank you!