is beehaw related to lemmy?

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Joined 1 year ago
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Cake day: June 8th, 2023

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  • Indeed, an integer is divisible by 3 if and only if the sum of its digits is divisible by 3.

    For proof, take the polynomial representation of an integer n = a_0 * 10^k + a_1 * 10^{k-1} + … + a_k * 1. Note that 10 mod 3 = 1, which means that 10^i mod 3 = (10 mod 3)^i = 1. This makes all powers of 10 = 1 and you’re left with n = a_0 + a_1 + … + a_k. Thus, n is divisible by 3 iff a_0 + a_1 + … + a_k is. Also note that iff answers your question then; all multiples of 3 have to, by definition, have digits whose sum is a multiple of 3






  • That wouldn't make sense either, because the user literally has to provide them all kinds of personal information in order to register. And no matter which IP address is being used to register, the user still has to pay to even use their service. So rejecting accounts simply because the registration was done via VPN is, in the best case scenario, overkill.

    Don't get me wrong though, I have nothing against them; I just don't think their anti-spam measures are anywhere as good as they need to be, and their responses towards people complaining about them indicate that they wouldn't bother trying to make it better.


  • I get the reason behind it, and support it too, but it doesn't make a good impression when your account gets rejected despite every information being correct just because you signed up using a VPN (I can't verify that VPN is the reason, but it has been suggested elsewhere to be a cause for suspicion on their part).


  • I tried them a couple days ago, got to setting up Hetzner API, had my account rejected a bunch of times, found out Hetzner team is infamous for rejecting new accounts and cancelling old accounts by the whims of their 'protection systems', realized the only other hosting option supported by SelfPrivacy is Digital Ocean, noped out of it all




  • I’ve been using it for a couple weeks but haven’t used RCS, so I can’t say specifically about that. Overall though, it’s still a work in progress and is not as polished but it gets the job done (more or less). If you’re really concerned about privacy using their closed source app, you can just host your own bridges in your Matrix server (the app is the only proprietary part of Beeper, the protocol is just Matrix). The app doesn’t support logging in from another Matrix account, so you’ll have to stick with Element (I think Element derivatives would work too) when using your own bridges. But that’s probably a better option given that their own app lacks a few features.


  • That’s some high IQ usage of a meme. Lemme see if I’m getting this right:

    • the total area of the image ( = RHS of the equation) is 1
    • you divide the image into 4 parts so that the area of 1 part is is 1/4 ( = 1/2^(2*1)). You take the first three quarters and leave the fourth quarter for recursion (I’ll call it x1). That gives you 3(1/4) + x1 = 1
    • now you take x1 and do the same with it. This time, the area of each sub-quarter is 1/16 ( = 1/2^(2*2)). Three such sub-quarters and a leftover x2 gives you 3(1/16) + x2 = x1. Put this back into the first equation to get 3(1/4 + 1/16) + x2 = 1.
    • repeat until infinity; each time the area of the resulting tile is 1/4 of the previous tile (which is the 2n in the exponent part)

    Edit: imma remove all markdown since it doesn’t seem to work, at least on liftoff. Enjoy the lisp-like mess